1.2 % NaCl solution is isotonic with 7.2 % glucose solution. What will be the van't Hoff factor, i?

Options

A. 0.5
B. 1
C. 2
D. 6

Answer

C

Explanation

`"For "NaCl," "pV=nRTxxi`
`p_(1)xx(100)/(1000)=(1.2)/(58.5)xx0.0821xxTxxi` . . . (i)
For glucose, `pV=nRT`
`p_(2)xx(100)/(1000)=(7.2)/(180)xx0.0821xxT` . . . (ii)
`because` NaCl and glucose solutions are isotonic
`:.p_(1)=p_(2),i=(7.2)/(180)xx(58.5)/(1.2)=1.95~~2`