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Henry's law constant for the molality of...

Henry's law constant for the molality of methane in benzene at `298K `is `4.27xx10^(5)mm Hg`. Calculate the solubility of methane in benzene at `298 K` under `760 mm Hg`.

A

`1.87xx10^(-5)`

B

`1.77xx10^(-3)`

C

`1.77xx10^(-4)`

D

`1.90xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
B
By Hebrt's law,
`p=K_(H)x`
`760=4.27xx10^(5)xxS`
`S=(760)/(4.27xx10^(5))=1.77xx10^(-3)`
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