The coordination number and the oxidation state of the element 'E' in the complex `[E(en)_2(C_2O_4)]NO_2` (where `(en)` is ethylenediamine) are, respectively

Options

A. 6 and 2
B. 4 and 3
C. 4 and 3
D. 6 and 3

Answer

D

Explanation

`en {:(CH_(2) -NH_(2)),(|),(CH_(2)-NH_(2)):}` is a bidetate ligand
is a bidentate ligand .
Hence , coordinating sites for ` [E(en)_(2))C_(2)O_(4))]^(+)NO_(2)^(-)`
Let , x be the charge on the E
` x+2(0) +(-2) =+1`
` x=+3`
` therefore ` Oxidation number is 3.