One mole of an organic compound A with the formula `C_(3)H_(8)O` reacts completely with two moles of HI to form X and Y. When Y is boiled with aquous alkali it forms Z.Z answers the iodoform test. The compound A is

Options

A. propane-2-ol
B. propane-1-ol
C. ethoxyethane
D. methoxyethane

Answer

D

Explanation

Molecular formula `C_(3)H_(8)O(C_(n)H_(2n+2)O)` suggests that the organic compound is either alochol or ether.
Since, the compound on reaction will HI gives two different compounds, it must be an unsymmetrical ether, and its formula must be `CH_(3)OC_(2)H_(5)` (methoxyethane).
`underset("Methoxyethane")(CH_(3)OC_(2)H_(5))+2HI rarr underset("X")(CH_(3)I)+underset("Y")(C_(2)H_(5)OH)`
`C_(2)H_(5)OH+underset("Aqueous")(6NaOH)+4I_(2) rarr underset("Iodoform")(CHI_(3))+HCOoverset(-)Ooverset(+)Na+5H_(2)O+"5NAI"`