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Propylene on hydrolysis with sulphuric a...

Propylene on hydrolysis with sulphuric acid forms

A

n-propyl alcohol

B

isopropyl alcohol

C

ethyl alcohol

D

butyl alcohol

Text Solution

Verified by Experts

The correct Answer is:
B
`underset("Propylene")(CH_(2)=CH)-CH_(3)+H_(2)Ooverset(H_(2)SO_(4))rarrunderset("isopropyl alcohol")(CH_(3)-overset(OH)overset("| ")"CH"-CH_(3))`
Thus, in this reaction isopropyl alcohol is formed.
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