Find the moment of inertia of a solid cylinder of mass M and radius R about a line parallel to the axis of the cylinder and on the surface of the cylinder.

Options

A. `3/2MR^(2)`
B. `1/2MR^(2)`
C. `7/5MR^(2)`
D. `2/5MR^(2)`

Answer

A

Explanation

The moment of inertia of the cylinder about is axis is
`(MR^(2))/2`.
Using parallel axis theorem.
`I=I_(0)+MR^(2)=(MR^(2))/2+MR^(2)=3/2MR^(2)`
Similarly the moment of inertia of a solid sphere about a tangent is
`2/3 MR^(2)+MR^(2)=7/5MR^(2)`