Three identical thin rods, each of mass `m` and length `l`, are joined to form an equilateral triangular frame. Find the moment of inertia of the frame about an axis parallel to tis one side and passing through the opposite vertex. Also find its radius of gyration about the given axis.

Explanation

To find the moment of inertia of the equilateral triangular frame made of three identical thin rods about an axis parallel to one side and passing through the opposite vertex, we can follow these steps:

### Step 1: Understand the Geometry of the Triangle
We have an equilateral triangle formed by three rods, each of mass \( m \) and length \( l \). Let's denote the vertices of the triangle as \( A \), \( B \), and \( C \). The axis of rotation is parallel to side \( AB \) and passes through vertex \( C \).

### Step 2: Identify the Moment of Inertia Contributions
The moment of inertia \( I \) about the axis can be calculated by considering the contributions from each rod:
- The rod \( AC \) is perpendicular to the axis and will contribute to the moment of inertia.
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