Two small kids weighing 10 g and 15 kg respectively are tyribg t balance a seesaw of total length 5.0 with the fulcrum at the centre. If one of the kids is sitting at an end where shold the other sit?

Explanation

If the kid of mass `15 kg` sit at the end, he will produce maximum torque about fulcrum.

The seesaw will not be balance for any position of kid of mass `10 kg`. It is clear that the `10 kg` kid should sit at the end the `15 kg` kid should sit closer to the centre. suppose his distance from the centre is `x`. As the kids are in equilibrium,the normal force between a kid and the see saw equals the weight of that kid. consider the rotational equilibrium add to zero. the forces are as follows:
a. `(15 kg)g=150N` downwards by the `15 kg` kid,
b. `(10 kg)=g=100 N` downwards by the `10 kg` kid,
c. weight of the seesaw, and
d. the normal force by the fulcrum
Taking torques about the fulcrum.
`150xxx=100xx2.5` or `x=1.7m`