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Figure shows an arrangement of masses hanging from a ceiling. In equilibrium, each rod is horizontal, has negligible mass and extends three times as far to the right of the wire supporting it as to the left. If mass `m_(4)` is `48 kg` then mass `m_(1)` is equal to

A

`1kg`

B

`2kg`

C

`3kg`

D

`4kg`

Text Solution

Verified by Experts

The correct Answer is:
A

`m_(2)g1=m_(1)g.3rarrm_(2)=3m_(1)`
`rarr4m-1g.3=m_(3)grarrm_(3)=12m_(1)`
`rarr16m_(1)g.3=m_(4)grarrm_(1)=48/48=1kg`
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