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From a complete ring of mass M and radiu...

From a complete ring of mass `M` and radius `R`, a `30^@`sector is removed. The moment of inertia of the incomplete ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is
,

A

`9/12MR^(2)`

B

`11/12MR^(2)`

C

`11.3/12MR^(2)`

D

`MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

Mass of incomplete ring
`=m-M/(2pi)xxpi/6=M-M/12=(11M)/12`
moment of inertia of incomplete ring
`((11M)/12)R^(2)=11/12MR^(2)`
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Knowledge Check

  • Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is

    A
    `1//2MR^(2)`
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    `MR^(2)`
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    A
    `3//4`
    B
    `7//8`
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    `1//4`
    D
    `1//8`
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