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A square plate ABCD of mass m and side l...

A square plate `ABCD` of mass `m` and side `l` is suspended with the help of two ideal strings `P` and `Q` as shown. Determine the acceleration (in `m//s^(2))` of corner `A` of the square just at the moment the string `Q` is cut. `(g = 10 m//s^(2))`.

Text Solution

Verified by Experts

The correct Answer is:
6
`T l/2 = (ml^(2))/6xxalpha, mg-T=ma`
`alpha=(3T)/(ml)=3/(ml)(mg-ma)`
Connstraint relation: Acceleration of `A` in the vertical direction should be zero.

`l/2alpha=a`
`implies alpha=(2a)/l=(3(g-a))/l`
`5a=3ggta=3xxg/5=6m//s^(2)`
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