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Four solid spheres each of diameter sqar...

Four solid spheres each of diameter `sqart5`cm and mass 0.5 kg are placed with their centers at the corners of a square of side 4cm. The moment is `Nxx10^(-4)kg - m^2` , then N is .

Text Solution

Verified by Experts

The correct Answer is:
9


`I=(2/5MR^(2))2+(2/5MR^(2)+Mx^(2))2`
`(2/5MR^(2))2+(2/5MR^(2))=(Mx^(2))2`
`=4(2/5MR^(2))+2Mx^(2)=8/5MR^(2)+2mx^(2)`
`=[8/5xx0.5xx(sqrt(5)/2)^(2)+2xx(0.5)xx84xx2)]10^-4`
`=[5/5+8]xx10^(-4)=9xx10^(-4)=Nx10^(-4)`
So, `N=9`
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