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a xx [axx(axxb)] is equal to...

`a xx [axx(axxb)]` is equal to

A

`(a xx a).(b xx a)`

B

`a. (b xx a)-b (a xx b)`

C

`[a. (a xx b)]a`

D

`(a.a) (b xx a)`

Text Solution

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The correct Answer is:
C
`axx[axx(axx)]=a{(a*b)a-(a*a)b}`
`=0-(a*a)(axxb)=(a*a)(bxxa)`
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