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Figure shows a method for measuring the ...

Figure shows a method for measuring the acceleration due to gravity. The ball is projected upward by a gun. The ball pases the electronic gates `1` and `2` as it rises and again as it falls. Each gate is connected to a separate timer. The first passage of the ball through each gate stars the corresponding timer, and the second passage through the same gate stops the timer. the time intervals `/_\t_(1)` and `/_\t_(2)` are thus measured. The vertical distance between the two gates is `d`. If `d=5m, /_\t_(1)=3s, /_\t_(2)=2s`, then find the measured value of acceleration due to gravity (in `m//s^(2)`)

A

`8ms^(-2)`

B

`4ms^(-2)`

C

`2ms^(-2)`

D

`1ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`(v_(1))/a=(/_\t_(1))/2=1.5`
`(v_(2))/a=(/_\t_(2))/2=1`
`d=(v_(1)^(2)-v_(2)^(2))/(2a)impliesa=8m//s^(2)`
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