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The ratio of tensions in the string conn...

The ratio of tensions in the string connected to the block of mass `m_(2)` in figure, respectively, is (friction is absent everywhere):`[m_(1)=50 kg, m_(2)=80kg` and `F=1000N]`

A

`7:2`

B

`2:7`

C

`3:4`

D

`4:3`

Text Solution

Verified by Experts

The correct Answer is:
C
In fig a in the question let tension in the string be `T_(1)`.
`F-T_(1)=m_(1)a`
`implies1000-T_(1)=50a`…………i
`T_(1)-m_(2)=m_(2)a`
`implies T_1-80g=80a`………..ii
From eqn i and i `T_1=12000/13N`
In fi b, in the equation, let tension in the string be `T_2`
`F+m_1g-T_2=m_1 a`
`implies1000+50g=T_2=50a`...........iii
`T_2=80g=80a`............iv
From eqn iii and iv we get
`T_2=16000/13NimpliesT_1/T_2=12000/16000=3/4`
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