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A soap bubble of raidus R is surrounded ...

A soap bubble of raidus `R` is surrounded by another soap bubble of radius `2R`, as shown. Take surface tension `=S`. Then the pressure inside the smaller soap bubble, in excess of the atmosphere presure will be

A

`4S//R`

B

`3S//R`

C

`6S//R`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`P_1-P_0=(4S)/(2R)`…………i
`P_2-P_1=(4S)/R`………….ii

From eqn i and ii
`P_2-P_0=(6S)/R`
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