The cone of radius `R` and height `H` is hanging inside a liquid of density by means of a string a shwon in the figure.

Options

A. Net force on the cone by the liquid is equal to buoyancy force on the cone.
B. Force on the bottom surfae of the cone is more than buoyancy force on the cone.
C. Net force on the slant surface of the cone is more than buoyancy force on the cone.
D. Net force on the slant surface of the cone is less than buoyancy force on the cone.

Answer

A, B, C

Explanation

`B=F_B-F_S`, where `F_S` is the net vertical downward force on the slant surface and `F_B` is net force on the bottom surface.

`B=Vrhog=1/3piR^2rhog, F_B=rhogHpiR^2`
Now `F_s=F_b-B`
`impliesF_S=rhogHpiR^2-(HrhogpiR^2)/3=2/3rhogHpiR^2`
Clearly `F_BgtB,F_SgtB`