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We apply a force of 10N on a cord wrappe...

We apply a force of `10N` on a cord wrapped around a cylinder of mass `2kg`. The cylinder rolls without slipping on the floor. What is the kinetic energy (in joule) when cylinder has moved by a distance of `3//5` m?

Text Solution

Verified by Experts

The correct Answer is:
6
Since `10lt ltmg` the cylinder rolls on the ground without lifting up. Therefore,
`KE="workdone"=Fxx"displacement"=10xx3/5=6J`
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