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A block of wood of density 500 kg//m^(3)...

A block of wood of density `500 kg//m^(3)` has mass `m` kg in air. A lead block which has apparent weight of `28 kg` in water is attached to the block of wood, and both of them are submerged in water. If their combined apparent weight in water is `20 kg`, find the value of `m`. Take density of water `=1000kg//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
8
`rho_wV_w=m` density of `H_2O: rho_H=1000`
Given `rho_LV_L-rho_HV_L=28` and
`rho_LV_L+rho_wV_w-rhoH(V_L+V_w)=20`
`implies28+m-rho_HV_w=20`
`implies 28+m-rho_Hm//rho_w=20`
`impliesm=8kg`
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