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Calculate the mole fraction of H(2)SO(4)...

Calculate the mole fraction of `H_(2)SO_(4)` in a solution containing `98% H_(2)SO_(4)` by mass.

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Given a solution containing - `98% H_(2)SO_(4)` by mass.
It means 98 gms of `H_(2)SO_(4)` and 2 gms of `H_(2)O` mixed to form a solution.
`n_(H_(2)O)=("Weight")/("GMW")=(2)/(18)=(1)/(9)`
`n_(H_(2)S_(o4)=("Weight")/("GMW")=(98)/(48)=1`
Mole fraction of `H_(2)SO_(4)." X"_(H_(2)SO_(4))=(n_(H_(2)SO_(4)))/(n_(H_(2)O)+n_(H_(2)SO_(4)))`
`=(1)/(1//9+1)=(9)/(10)=0.9`
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