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How is molar mass related to the elevati...

How is molar mass related to the elevation in boiling point of a solution ?

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The expression for elevation of boiling point is
`DeltaT_(b)=(K_(b)xx1000xx w)/(m xx w)=K_(b)=" molal elevation constant"`
w = Weight of solute
W = Weight of solvent
m = molar mass of solute
Molar mass of solute m `=(K_(b)xx1000xx w)/(DeltaT_(b)xx w)`
`:.` Molar mass of solute (m) and elevation of boiling point `(DeltaT_(b))` are inversely related.
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When some amount of non-volatile solute is dissolved in a solvent to prepare a dilute solution, the vapour pressure of the solvent is lowered and it is directly proportional to the mole fraction of solvent in the solution . Relative lowering in vapour pressure is equal to mole fraction of solute . Elevation in boiling point of solvent is a collgative property like lowering in vaour pressure of solvent in solution , K_(b) i.e., molal elevation constant is calculated by the formula, K_(b)=DeltaT_(b)// molality and also by the expression, K_(b)=RT_(b)^(2)//1000l_(v) where T_(b) is boiling point of solvent and I_(v) is latent heat of vapourisation for 1 gm solvent . Abnormal elevation is boiling point =iX elevation in boiling point in ideal solution where i=van't Hoff factor Relative lowering in vapour pressure :

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