Calculate the osmotic pressure in Pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 1,85,000 in 450 mL of water at `37^(@)C`.
Use the formula for osmotic pressure `(pi)="CRT and C"=(n)/(V)" and n"=(W_(B))/(M_(B))`

Explanation

Mass of polymer `(W_(B))=1.0" g"`
Molar mass of polymer `(M_(B))=185000" g mol"^(-1)`
Volume of solution (V) `=450" mL"=0.450" L"`
Temperature (T) = `37+273=310" K"`
Solution constant ( R ) `=8.314xx10^(3)" Pa L K"^(-1)" mol"^(-1)`
Osmotic pressure `(pi)=CRT`
`=(W_(B)xxRxxT)/(M_(B)xxV)`
`pi=((1.0" g")xx(8.314xx10^(3)" Pa L K"^(-1)" mol"^(-1))xx(310" K"))/((185000" g mol"^(-1))xx(0.450" L"))`
`=30.96" Pa"`