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Calculate the emf of the cell at 25^(@)C...

Calculate the emf of the cell at `25^(@)C`
`Cr|Cr^(3+)(0.1M)||Fe ^(2+)(0.01M) |Fe,` given that `E_(Cr^(3+)//Cr )^(0)=-0.74V and E_(Fe ^(2+)//Fe )^(0)=-0.44V`

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Given cell is
`Ce|Cr _((0.1M))^(+3)||Fe_((0,01M))^(+2)|Fe`
`E^(0) of Cr ^(+3)//Cr =-0.74V`
`E^(0)of F^(+2)//Fe =-0.44V`
`E_(Cr^(3)//C)=E^(0) +(0.059)/(3)log _(10) [Cr^(+3)]`
`=-0.74+(0.054)/(3)log 0.1`
`=-0.76V`
`E_(Fe^(+2)//Fe) =-0.44+(0.059)/(2)log 0.01`
`=-0.44-0.059=-0.499V`
EMF of cells `=E_(RHS) -E_(LHS)`
`=(-0.499) -(-0.76)=0.261V`
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