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Determine DeltaG^(0) for the button cell...

Determine `DeltaG^(0)` for the button cell used in the watches. The cell reactions is
`Zn_((s))+Ag _(2)O_((s))H_(2)O _((l))to Zn_((aq))^(2+)+2 Ag _((s))+2OH_((aq))^(-)`
`E_(Ag^(+)//Ag)^(0) =+0.80V,E_(Zn^(2+)//Zn)^(0)=-0.76V.`

Text Solution

Verified by Experts

Given `E^(0) of Ag^(+)//Ag =0.80 V`
`E^(0) of Z n ^(+2)//Zn =-0.76V`
Cell representation `Zn //Zn^(+2)||Ag^(+)//Ag`
`EMF=E_(RHS)-E_(LHS) =0.80-(-0.76)=1.56V`
`DeltaG=-nFE^(0)=-2xx96500xx1.53=-301.08kJ//"mole"`
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