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Calculate the emf of the cell at 298 K ...

Calculate the emf of the cell at 298 K
`Sn_((s))|Sn^(2+)(0.05M)||H_((aq))^(+)(0.02M) |H_(2)` 1 atm. Pt
Given that `E_(sn^(2+)//Sn)^(0)=-0.144V`

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Cell equation `: Sn _((s))+2H_((aq))^(+)to Sn _((aq))^(+)+H_(2(g))`
Nernst equation `:E_(cell)=E_(cell)^(0)-(0.0591)/(2)log ""([Sn^(2+)])/([H^(+)]^(2))`
EMF of the cell `E_(cell) =[0-(-0.14)]-(0.0591)/(2)log ""([0.05])/([0.02]^(2))`
`=0.14-(0.0591)/(2)xx[2.097]=0.14-0.0620=0.078V`
`EMF=0.078V`
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