The conductivity of `0.20M` solution of KCl at 298 K is `0.0248S cm^(-1).` Calculate molar conductance.

Explanation

Conductivity `(k) =0.0248S cm^(-1)=0.0248 ohm^(-1) cm^(-1)`
Molar concentration `[c] =0.20mol L^(-1)`
`=([0.2mol])/([1000cm^(3)])=2.0xx10^(-4)mol cm ^(-3)`
Molar conductivity `[^^_(m)]=k/c=([0.0248ohm^(-1)cm^(-1)])/([2.0xx10^(-4)mol cm^(-3)])`
`=124 ohm^(-1) cm ^(-2)or 1245 mol ^(-1)cm^(2)`
Molar condu tivity `=124s mol ^(-1) cm^(2)`