In a reaction `2A to ` Products, the concentration of A decreases from `0.5 mol I^(-1)` to `0.4 mol L^(-1)` in 10 minutes. Calculate the rate during this interval.

Explanation

`2A to` products
`0.5 -0.4` mol lit rate `prop [A]^(2)`
rate `=(-1)/(2) (d)/(dt) [A]=1/2 [((0.5-0.4))/(10)]=0.5xx10^(-2)`
rate `=5xx10^(-3) mol Lit ^(-1) min ^(-1)`