The decomposition of `NH_(3)` on platjinum surface is zero order reaction. Want are the rates of production of `N_(2) and H_(2) if k=2.5 xx10^(-4) mol ^(-1) Ls^(-1).`

Explanation

For a zero order reaction
rate `=(dx)/(dt)=k.`
`dx=` charnge in the concentration
`dt=` difference in time
`k=` rate constant
`{:(2NH_(3) , hArr, N_(2), + , 3H_(2)),("2 moles",,"1 mole",, "3 mole"):}`
Rate of production of `N_(2) =k= 2.5xx10^(-14) mol L^(-1) s^(-1)`
Rate of production of `H_(2) =3xx 2.5 xx10^(-14) =7.5 xx10^(-4) mol L ^(-1)s^(-1).`