Consider a certain reaction `A to` Products with `k=2.0 xx10^(-2)s^(-1).` Calculate the concentration of A remaining after 100 s if the initial concentration of A is `1.0 mol L^(-1).`

Explanation

For the first order reaction
`t=(2.303)/(k )log""([A]_(0))/([A])`
`or log ""([A]_(0))/([A])=(kxxt)/(2.303)`
`k=2.0 xx10^(-2)s^(-1), t=100S,`
`[A]_(0)=1.0 mol L^(-1)=1.0M`
`log ""([A_(0)])/([A])=((2.0 xx10^(-2)s^(-1))xx(100s))/(2.303)=0.8684`
`([A_(0)])/([A])="Antilog" 0.8684 =7.3858`
`[A] =([A]_(0))/(7.3858)=([1M])/(7.3858)=0.135M`
`[A] =0.135M`