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The decomposition of hydrocarbon follows...

The decomposition of hydrocarbon follows the equation
`K=(4.5xx10^(11) s^(-1))e^(-18000K//T).` Calculate `E_(a).`

Text Solution

Verified by Experts

According to the available data
`k=Ae ^(-E_(a)//RT)-(i)`
According to the available data
`k=(4.5xx10s^(-1))e^(-28000)k//T-(ii)`
on comparing both equations
`-(E_(a))/(RT)=(-2800k)/(T)`
`E_(a) =(28000k)xxR`
`=(28000k)xx(8.314K^(-1)J mol^(-1))`
`=232792Jk mol^(-1)`
`E_(a) =231.792 kJ^(-1) mol ^(-1)`
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