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Why is the reduction of a metal oxide if...

Why is the reduction of a metal oxide if the metal formed is in liquid state at the temperature of reduction?

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The entropy is higher if the metal is in liquid state than when it is in solid state than when it is . The value of entropy change `(DeltaS)` of the reduction process is more on +ve side When the metal formed is in liquid state and the metal oxide being is in solid State. Thus the value of `DeltaG^(Theta)` becomes more on negative side and the reduction becomes easier.
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