Home
Class 12
CHEMISTRY
Explain the shape of XeF(4) on the basis...

Explain the shape of `XeF_(4)` on the basis of VSEPR theory.

Text Solution

Verified by Experts

Shape of `XeF_(4)` :
1) Central atom in `XeF_(4)` is 'Xe'.
2) Xe undergoes `sp^(3)d^(2)` hybridisation in it's `2^(nd)` excited. State.

3) Shape of the molecule is square planar with bond angle `90^(@)` and bond length `1.95Å`.

4) Xe - forms four `sigma`-bonds by the overlap of `sp^(3)d^(2)-2p_(z)`(F) orbitals.
Promotional Banner

Topper's Solved these Questions

  • P-BLOCK ELEMENTS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise GROUP 15 ELEMENTS (SHORT ANSWER QUESTIONS)|21 Videos

  • P-BLOCK ELEMENTS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise GROUP 16 ELEMENTS (SHORT ANSWER QUESTIONS)|21 Videos

  • P-BLOCK ELEMENTS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise DAM SURE VSAQ - 2 Marks|8 Videos

  • ORGANIC COMPOUNDS CONTAINING NITROGEN

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise DAM SURE (SAQ - 8 Marks)|15 Videos

  • POLYMERS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise INTEXT QUESTIONS|6 Videos

Similar Questions

Explore conceptually related problems

Discuss the molecular shape of "BrF"_(3) on the basis of VSEPR theory.

Explain the structures of XeF_(4)

The shape of XeF_6 is

Explain the structures of XeF_(6)

Explain the structures of XeF_(2)

What is the use of VSEPR theory?

Write about VSEPR theory.

Explain the shape of water molecules.

Explain photoelectric effect on the basis of Einstein theory.