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How are XeF(2),XeF(4),XeF(6) prepared ? ...

How are `XeF_(2),XeF_(4),XeF_(6)` prepared ? Give equation.

Text Solution

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`underset(("Xenon in excess"))("Xe (g)"+F_(2))(g)overset(673"K",1" bar")to"XeF"_(2)(S),`
`underset((1:5" ratio"))("Xe (g)"+2F_(2))(g)overset("873, 7 bar")to"XeF"_(4)(S)`
`underset((1:20" ratio"))("Xe (g)"+3F_(2))(g)overset("573K, 70 bar")to"XeF"_(6)(S)`
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