A 3.0 cm wire carrying a current of 10 A is palaced inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire ?

Explanation

Here, the angle between the magnetic field and the direction of flow of current is `90^(@)`. Because the magnetic field due to solenoid is along the axis of solenoid and the wire is placed perpendicular to the axis.
Given, `l=3 cm =3xx10^(-2)m, I=10 A, B=0.27 T`
`f= I l B sin 90^(@)`
`=10xx3xx10^(-2)xx0.27=8.1xx10^(-2) N`
According to right hand palm rule, the direction of magnetic forces is perpendicular to plane of paper inwards.