Home
Class 12
PHYSICS
A square coil of side 10 cm consists of ...

A square coil of side 10 cm consists of 20 turns and carries current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of `30^(@)` with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experinced by the coil ?

Text Solution

Verified by Experts

Given, side of square coil =10 cm =0.1 m
Number of turns (n)=20
Current in square coil I=12 A
Angle made by coil `theta=30^(@)`
Magnetic field B=0.80 T
The magnitude of torque experinced by the coil
`tau =N I AB sin theta`
`=20xx12xx(10xx10^(-2))^(2)xx0.80xx sin 30^(@)`
`=0.96 N-m`
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES AND MAGNETISHM

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise ADDITIONAL EXERCISES|26 Videos

  • MOVING CHARGES AND MAGNETISHM

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise DAM SURE LAQ|2 Videos

  • MAGNETISM AND MATTER

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Additional Exercises|19 Videos

  • NUCLEI

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise DAM SURE (VSAQ)|1 Videos

Similar Questions

Explore conceptually related problems

A coil of 100 turns and area 5 square centimetre is placed in a magnetic field B = 0.2T. The normal to the plane of the coil makes an angle of 60^(@) with the direction of the magnetic field. The magnetic flux linked with the coil is

What is the magnitude of magnetic force per unit length on a wire carrying a current of 8A and making an angle of 30^(@) with the direction of a uniform magnetic field of 0.15 T ?

A circular coil of radius 10cm with 100 turns carrying a current of 0.5A lies in a magetic field of 2 T such that the normal drawn to the plane of the coil makes an angles theta with the direction of the field. Work done in rotating the coil to change the angle theta from 0^(@) to 180^(@) is

A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil ?

Circular coil of 30 turns, and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60^(@) with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil form turning.

(a) A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60^@ with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning. (b) Would your answer change, if the circular coil in (a) were replaced by a planar coil of some irregular shape that encloses the same area? (All other particulars are also unaltered.)