Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

Explanation

Change in current, dI= 5-0 =5A, Time taken in current change dt = 0.1s Induced average emf `e_(av)= 200 V` Induced emf in the circuit `e =L (dI)/(dt) Rightarrow 200=L((5)/(0.1)) or L=(200)/(50)=4H