Home
Class 12
PHYSICS
Calculate the (a)momentum and (b) de - B...

Calculate the (a)momentum and (b) de - Brogile wavelength of the electrons accelerated through a potential difference of 56 V.

Text Solution

Verified by Experts

Mass of the electron , m = `9 xx 10^(-31) " kg , "` Potential difference , V - 56 V
Momentum of electrons , mv = ` sqrt ( 2 e V m ) = sqrt(2 xx (1.6 xx 10^(-19) )xx56 xx 9 xx 10^(-31))= 4.02 xx 10^(-24) " kg ms"^(-1)`
(b) de - Broglie wavelength , ` lambda = h/p = h/(m v)= (6.62 xx 10^(-34))/(4.04 xx 10^(-24))= 1.64 xx 10^(-10) m `
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise TEXTUAL EXAMPLES|8 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise VERY SHORT ANSWER QUESTIONS|8 Videos

  • CURRENT ELECTRICITY

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise ADDITIONAL EXERCISES|22 Videos

  • ELECTRIC CHARGES AND FIELDS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise DAM SURE LAQ|1 Videos

Similar Questions

Explore conceptually related problems

Calculate the (a) momentum, and (b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.

Calculate the de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.

What is the de Broglie wavelength associated with an electron , accelerated through a potential difference of 100 volts ?

A proton when accelerated through a potential difference of V, has a De-Broglie wavelength lambda associated with it.if an alpha -particle is to have the same De-Broglie wavelength lambda, it must be accelerated through a potential difference of

If lamda_(0) is the De-Broglie wavelength for a proton accelerated through a potential difference of 100 V, De- Broglie wavelength for prop- particle accelerated through the same potential difference is

Calculate the wavelength of an electron that has been accelerated in a particle accelerator through a potential difference of 100 million volts.

The de Broglie wavelength of an electron is 1A^(@) . In what potential difference electron accelerates