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What is the de Broglie wavelength asso...

What is the de Broglie wavelength associated with an electron , accelerated through a potential difference of 100 volts ?

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Accelerating potential V=100 V . The de Brogile wavelength `lambda` is
` lambda = h//p = (1.227)/(sqrt(V))` nm
` lambda = (1.227)/(sqrt(100)) "nm" = 0.123` nm
The de Brogile wavelength associated with an electron in this case is of the order of X- ray wavelengths .
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