The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which
A neutron, and would have the same de Broglie wavelength.

Explanation

Given, `lambda = 589 nm = 589xx10^(-9)m, m_(e )=9.1xx10^(-31)kg`.
`m_(n)=1.67xx10^(-27)kg, h = 6.62xx10^(-34)J-s`.
`KE_(n)=(h^(2))/(2m_(n)lambda^(2))=((6.63xx10^(-34))^(2))/(2xx(1.66xx10^(-27))xx(589xx10^(-9))^(2)) therefore KE_(n) = 3.81xx10^(-28)J`.