An electron and a photon each have a wavelength 1.00 nm. Find
(i) their momenta,
(ii) the energy of the photon and
(iii) the kinetic energy of electron.

Explanation

Given, `lambda = 1 mm = 10^(-9)m, h = 6.63xx10^(-34)J - s, c = 3xx10^(8)m//s`
`P_(e )=(h)/(lambda)=(6.63xx10^(-34))/(10^(-9))=6.63xx10^(-25)m rArr P_(ph) = (h)/(lambda)=(6.63cc10^(-34))/(10^(-9))=6.63xx10^(-25 m`.