An X - ray tube produces a continous spectrum of radiation with its short wavelength end at 0.45 `Å` . What is the maximum energy of a photon in the radiation?

Explanation

Given , ` lambda = 0.45 Å = 0.45 xx 10^(-10) m, E = (hc)/lambda = (6.63 xx 10^(-34) xx 3 xx 10^(8))/(0.45 xx 10^(-10) xx 1.6xx 10^(-19) ) eV `
` :. E = 27.6 xx 10^(3) eV = 27.6 KeV`