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The radius of the oxygen nucleus .(8)^(1...

The radius of the oxygen nucleus `._(8)^(16)O` is `2.8xx10^(-15)m`. Find the radius of lead nucleus `._(82)^(205)Pb`.

Text Solution

Verified by Experts

`R_(0)=2.8xx10^(-15)m , A_(0)=16`
`A_(Pb)=205 , R_(Pb) = ?`
`(R_(Pb))/(R_(0))=[(A_(Pb))/(A_(0))]^(1//3)=[(205)/(16)]^(1//3)`
`[because R=R_(0)A^(1//3)]`
`(R_(Pb))/(2.8xx10^(-15))=(12.82)^(1//3)=2.34`
`R_(Pb)=(2.34)xx2.8xx10^(_15)`
`= 6.55xx10^(-15)m`
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