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Find the binding energy of .(26)^(56)Fe....

Find the binding energy of `._(26)^(56)Fe`. Atomic mass of Fe is 55.9349u and that of Hydrogen is 1.00783u and mass of neutron is 1.00876u.

Text Solution

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Mass of hydrogen atom
`m_(p)=1.00876u , m_(n)=1.00867u`
`Z=26, A = 56`
Mass of Iron atom M = 55.9349u
(i) Mass defect `Delta M`
`= [Zm_(P)+(A-Z)m_(n)-M]`
`=[26xx1.00876+(56-26)(1.00867)-55.9349]u`
`therefore Delta m = 0.55296u`
(ii) BE of nucleus `= Delta MC^(2)`
`= Delta M xx 931.5 MeV`
`= 0.55296(931.5) MeV`
`= 515.08 MeV`
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