Home
Class 12
PHYSICS
Calculate The binding energy per nucl...

Calculate
The binding energy per nucleon of `._(6)^(12)C` nucleus. Nuclear mass of `._(6)^(12)C=12.000000 u`, mass of proton = 1.007825 u and mass of neutron = 1.008665 u.

Text Solution

Verified by Experts

For `._(6)^(12)C, A=12, Z = 6, m_(P)=1.007825u`
`m_(n)=1.008665u ' M = 12.000000 u`
BE per nucleon
`= (B.E)/(A)=(92.16)/(12)=7.68 MeV`
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXAMPLES TEXTUAL|7 Videos
  • NUCLEI

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise SAMPLE PROBLEMS|4 Videos
  • MOVING CHARGES AND MAGNETISHM

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise ADDITIONAL EXERCISES|26 Videos
  • RAY OPTICAL AND INSTRUMENTS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise TEXTUAL EXERCISES|60 Videos

Similar Questions

Explore conceptually related problems

Calculate the (i) mass defect, (ii) binding energy and (iii) the binding energy per nucleon of ""_(6)^(12)C nucleus. Nuclear mass of ""_(6)^12C = 12. 000000 u, mass of proton=1.007825 u and mass of neutron=1.008665 u.

Calculate the binding energy per nucleon of ._(17)^(35)Cl nucleus. Given that mass of ._(17)^(35)Cl nucleus = 34.98000 u, mass of proton = 1.007825u, mass of neutron = 1.008665u and 1 is equivalent to 931 MeV.

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u, mass of a proton = 1.007825 u,, mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV.

How much energy is required to separate the typical middle mass nucleus ._(50)^(120)Sn into its constituent nucleons ? (Mass of ._(50)^(120)Sn=119.902199u , mass of proton = 1.007825u and mass of neutron = 1.008665u)

Find the average binding energy per nucleon of ._7N^14 and ._8O^16 . Their atomic masses are 14.008 u and 16.000 u. The mass of ._1H^1 atom is 1.007825 u and the mass of neutron is 1.008665 u. Which is more stable?