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How many disintegrations per second will...

How many disintegrations per second will Occur in one gram of `._(92)^(238)U`, if its half-life against `alpha`- decay is `1.42xx10^(-17)s` ?

Text Solution

Verified by Experts

`T=1.42xx10^(17)` sec
Decay constant `(lambda)=(0.693)/(T)=(0.693)/(1.42xx10^(7))`
No. of disintegration (n) in 1 gm
`= (1)/(238)xx6.023xx10^(23)`
`therefore` Activity `A = lambda N`
`= (0.693)/(1.42xx10^(17))xx(1)/(238)xx6.023xx10^(23)`
`= 1.235xx10^(4)` disintegrations / sec
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