Calculate the energy released by fission from 2g of `._(92)^(235)U` in kWh. Given that the energy released per fission is 200 MeV.

Explanation

Mass of uranium = 2 g
Energy per fission = 200 MeV
No. of atoms in 2g, `n = (2xx6.023xx10^(23))/(235)`
Total energy released (E') = nE
`= (2xx6.023xx10^(23))/(235)xx200xx10^(6)xx1.6xx10^(_19)J`
`= (2xx602.3)/(235)xx32xx10^(9)`
`= (1640.3xx10^(8))/(36xx10^(5))`
`therefore E'=45.56xx10^(3)` kWh
`= 4.556xx10^(4)` kWh