Home
Class 12
PHYSICS
Explain alpha- decay ?...

Explain `alpha`- decay ?

Text Solution

Verified by Experts

1. It is the phenomenon of emission of an `alpha` particle from a radioactive nucleus. When a nucleus emits an alpha particle, its mass number decreases by 4 and charge number decreases by 2.
2. In general, alpha decay is represented as
`._(Z)X^(A) rarr ._(Z-2)Y^(A-4)+ ._(2)He^(4)+Q`
Where Q is the energy released in the decay.
3. Thus the total mass energy of the decay products is less than the mass energy of the original nuclide.
4. The difference between the initial mass energy and the total mass energy of decay products is called disintegration energy (Q) of the process.
5. This can be calculated using Einstein's mass energy equivalence relation, `E = (Delta m). c^(2)`
i.e., `Q=(m_(x)-m_(y)-m_(He))c^(2)`
The energy released (Q) is shared by daughter nucleus y and alpha particle.
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise LONG ANSWER QUESTIONS|2 Videos
  • NUCLEI

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise TEXTUAL EXERCISES|32 Videos
  • NUCLEI

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise VERY SHORT ANSWER QUESTIONS|20 Videos
  • MOVING CHARGES AND MAGNETISHM

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise ADDITIONAL EXERCISES|26 Videos
  • RAY OPTICAL AND INSTRUMENTS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise TEXTUAL EXERCISES|60 Videos

Similar Questions

Explore conceptually related problems

Explain gamma - decay ?

Explain beta - decay ?

The half life of ""_(92)^(238)U against alpha - decay is 13.86xx10^(16) s . The activity of 1 g sample of is

How many disintegrations per second will Occur in one gram of ._(92)^(238)U , if its half-life against alpha - decay is 1.42xx10^(-17)s ?

The emission of penetraing alpha , beta particle (""_(2) ^(4) He and ""_(-1)^(0)e respectively ) along with gamma - radiation (hv) was noticed from unstable nuclei . All elements having Z gt 82 show this phenomenon . The emission was explained in terms of low binding energy (giving alpha - decay) high n/p ratio (neutron decay) , gamma from a radioactive nuclide is secondary emission. An element of group III with At. no. 90 and mass number of 238 undergoes decay of one alpha - particle . The newly formed element belongs to :

The emission of penetraing alpha , beta particle (""_(2) ^(4) He and ""_(-1)^(0)e respectively ) along with gamma - radiation (hv) was noticed from unstable nuclei . All elements having Z gt 82 show this phenomenon . The emission was explained in terms of low binding energy (giving alpha - decay) high n/p ratio (neutron decay) , gamma from a radioactive nuclide is secondary emission The emission of penetrating rays from a radioactive species can be shielded by

The emission of penetraing alpha , beta particle (""_(2) ^(4) He and ""_(-1)^(0)e respectively ) along with gamma - radiation (hv) was noticed from unstable nuclei . All elements having Z gt 82 show this phenomenon . The emission was explained in terms of low binding energy (giving alpha - decay) high n/p ratio (neutron decay) , gamma from a radioactive nuclide is secondary emission The binding energy of the hydrogen nucleus is :

The half-life of ._(92)^(238)U undergoing alpha - decay is 4.5xx10^(9) years. What is the activity of 1g sample of ._(92)^(238)U ?

In how many way among the following , a nucleus with high n/p ratio is expected to decay alpha - decay , beta - decay , positron decay , electron capture .