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Suppose that 1.0g fo hydrogen is separat...

Suppose that `1.0g` fo hydrogen is separated into electrons and protons. Suppose also that the protons are palced at the earth's north pole and the electrons are placed at the south pole. What is the resulting compression force on earth? (Given that the radius of rarth is 6400 km).

Text Solution

Verified by Experts

The correct Answer is:
`=5.10 kN`

Number of electrons or protons in 1.00 g of hydrogen is
`n=2[1/2xx6.023xx10^(23)]=6.023xx10^(23)`
Magnitude of charge on north or south pole is
`q="ne"=6.023xx10^(23)xx1.6xx10^(-19)=96368 C`
`F=(kq^2)/(r^2)=(9xx10^(9)xx(96368)^(2))/((2xx6400xx10^(3))^(2))=5.10xx10^(5)N`
`=5.10 kN`.
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Knowledge Check

  • You have 10^(23) carbon atoms imagine that all the nuclei are put at the north pole of the earth and the electron at the south pole of the earth (radius = 6400 km.) Then force between the charges is (Approx)-

    A
    `5 xx 10^(5)N`
    B
    `2 xx 10^(6)N`
    C
    `13.6 xx 10^(3)N`
    D
    `2 xx 10^(5)N`
  • What is the percentage change in the value of g as we shift from equator to pole on the surface of earth ? (Given equatorial radius of earth is greater than polar radius by 21 km and mean radius of earth is 6300 km ).

    A
    `0.52%`
    B
    `0.67%`
    C
    `1.67%`
    D
    `6.7%`
  • A body weighs 49 N on a spring balance at the north pole. What will be its weight recorded on the same weighing machine, if it is shifted to the equator ? (Use g =(GM)/R^2=9.8 ms^(-2) and radius of earth, R = 6400 km.]

    A
    49 N
    B
    49.83 N
    C
    48.83 N
    D
    49.17 N
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