Three charged paricles are placed on a straight line as shown in fig. `q_(1)` and `q_(2)` are fixed but `q_(3)` can be moved. Under the action of the forces from `q_(1),q_(2)` and `q_(3)` is in equilbrium. What is the relation between `q_(1)` and `q_(2)`.

Options

A. `q_(1)=4q_(2)`
B. `q_(1)=-q_(2)`
C. `q_(1)=-4q_(2)`
D. `q_(1)=q_(2)`

Answer

C

Explanation

Net force on `q_(3)` is `F_(1)+F_(2)=0`

or ,`(kq_(1)q_(3))/((2x)^(2))+(kq_(2)q_(3))/(x^(2))`.