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Three charged paricles are placed on a s...

Three charged paricles are placed on a straight line as shown in fig. `q_(1)` and `q_(2)` are fixed but `q_(3)` can be moved. Under the action of the forces from `q_(1),q_(2)` and `q_(3)` is in equilbrium. What is the relation between `q_(1)` and `q_(2)`.

A

`q_(1)=4q_(2)`

B

`q_(1)=-q_(2)`

C

`q_(1)=-4q_(2)`

D

`q_(1)=q_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Net force on `q_(3)` is `F_(1)+F_(2)=0`

or ,`(kq_(1)q_(3))/((2x)^(2))+(kq_(2)q_(3))/(x^(2))`.
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Knowledge Check

  • Three charges -q,+Q and -q are placed in a straight line as shown If the total potential energy of the system is zero, then the ratio (q)/(Q) is

    A
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    B
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    C
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  • The value of charge q_1 ,q_2 and q_3 as shown in the figure are

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    B
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    C
    `q_1 =32 mu C ,q_2 =24 mu C ,q_3 =+ 8muC `
    D
    ` q_1 =3mu C ,q_2 =4muC ,q_3 =+ 2mu C `

  • Threee charges +Q_(1),+Q_(2) and q are placed on a straight line such that q is somewhere in between +Q_(1) and Q_(2) . If this system of charges is in equlibirium what should be the magnitude and sign of charge q?

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    B
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    C
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    D
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