A particle of mass m carrying a positive charge q moves simple harmonically along the x-axis under the action of a varying electric field E directed along the x-axis. The motion of the particle is confined between x=0 and x=2l. The angular frequency of the motion is `omega`. Then which of the following is correct ?

Options

A. `qE=-momega^(2)(x-1)`
B. `qE=momega^(2)(x-1)`
C. Electric field to the right of origin is directed along the positive x-axis for all balues of x.
D. Electric field to the right of origin is directed along the negative x-axis for all balues of x.

Answer

A

Explanation

Mean position : x=1
`F=-k(x-l)` where `k=m, omega^(2)`
or `qE=-m omega^(2)(x-l)At x=l, E=0`
To the right of x=l, E is negative, so toward left and to the left of x=l, E is positive.